supplier evaluation using population proportion tests hypothesis
Case Study:
A manufacturer of walk-behind push mowers receives refurbished small
engines from two new suppliers, A and B. It is not uncommon that some of the
refurbished engines need to be lightly serviced before they can be fitted into
mowers. The mower manufacturer recently received 100 engines from each
supplier. In the shipment from A, 13 needed further service. In the shipment
from B, 10 needed further service. Test, at the 10% level of significance,
whether the data provide sufficient evidence to conclude that there exists a difference in the proportions of engines from the two suppliers needing
service.Solutions:
#Input:
sample_A_size = 100
sample_A_prop = 0.13
sample_B_size = 100
sample_B_prop = 0.10
alfa = 0.10
#STEP 1: Hypo
#H0 = Pa - Pb = D0 = 0: no difference in the test population
#Ha = Pb != Pb : there is a differenc in supplier products
#STEP 2 & 3: statistic test
z_statistic = (sample_A_prop - sample_B_prop - 0 )/
sqrt((sample_A_prop*(1- sample_A_prop) + sample_B_prop*(1-sample_B_prop))/ sample_A_size )
#STEP 4 & 5 Rejection Region:
z_value = - qnorm(.05,
mean = 0,
sd = 1)
c(between(z_statistic, z_value, Inf),
between(z_statistic, -Inf, - z_value))
#[1] FALSE FALSE
p_value = pnorm(z_statistic,
mean = 0,
sd = 1)
#[1] 0.747
Conclusion:
The test statistic does not fall in the rejection region. The
decision is not to reject H0. In the context of the problem our
conclusion is:
The data provide sufficient evidence, at the 10% level of
significance, to conclude that there exists no difference in the proportions of engines from the two suppliers needing service.
using p-value approach: since the p-value < alfa or the confidence level the decision is the same as above

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